JavaScript算法试题系列-04

题目要求：

// 乱序同字母字符串给定两个字符串，判断是否颠倒字母而成的字符串，譬如Mary与Army就是同字母而顺序颠倒：var firstWord = "Mary";
var secondWord = "Army";

isAnagram(firstWord, secondWord); // true

解答：

function isAnagram(first, second) {
  // For case insensitivity, change both words to lowercase.
  var a = first.toLowerCase();
  var b = second.toLowerCase();

  // Sort the strings, and join the resulting array to a string. Compare the results
  a = a.split("").sort().join("");
  b = b.split("").sort().join("");

  return a === b;
}